(1/3)^4x-3=27

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Solution for (1/3)^4x-3=27 equation: 



(1/3)^4x-3=27

We move all terms to the left:

(1/3)^4x-3-(27)=0



Domain of the equation: 3)^4x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^4x-3-27=0

We add all the numbers together, and all the variables

(+1/3)^4x-30=0

We multiply all the terms by the denominator


(+1-30*3)^4x=0

We add all the numbers together, and all the variables

(-89)^4x=0

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